Optimal. Leaf size=47 \[ \frac{a^2 \sinh (c+d x) \cosh (c+d x)}{2 d}+\frac{1}{2} a x (a+4 b)+\frac{b^2 \tanh (c+d x)}{d} \]
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Rubi [A] time = 0.0784786, antiderivative size = 47, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.174, Rules used = {4146, 390, 385, 206} \[ \frac{a^2 \sinh (c+d x) \cosh (c+d x)}{2 d}+\frac{1}{2} a x (a+4 b)+\frac{b^2 \tanh (c+d x)}{d} \]
Antiderivative was successfully verified.
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Rule 4146
Rule 390
Rule 385
Rule 206
Rubi steps
\begin{align*} \int \cosh ^2(c+d x) \left (a+b \text{sech}^2(c+d x)\right )^2 \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\left (a+b-b x^2\right )^2}{\left (1-x^2\right )^2} \, dx,x,\tanh (c+d x)\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int \left (b^2+\frac{a (a+2 b)-2 a b x^2}{\left (1-x^2\right )^2}\right ) \, dx,x,\tanh (c+d x)\right )}{d}\\ &=\frac{b^2 \tanh (c+d x)}{d}+\frac{\operatorname{Subst}\left (\int \frac{a (a+2 b)-2 a b x^2}{\left (1-x^2\right )^2} \, dx,x,\tanh (c+d x)\right )}{d}\\ &=\frac{a^2 \cosh (c+d x) \sinh (c+d x)}{2 d}+\frac{b^2 \tanh (c+d x)}{d}+\frac{(a (a+4 b)) \operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,\tanh (c+d x)\right )}{2 d}\\ &=\frac{1}{2} a (a+4 b) x+\frac{a^2 \cosh (c+d x) \sinh (c+d x)}{2 d}+\frac{b^2 \tanh (c+d x)}{d}\\ \end{align*}
Mathematica [A] time = 0.141845, size = 52, normalized size = 1.11 \[ \frac{a^2 (c+d x)}{2 d}+\frac{a^2 \sinh (2 (c+d x))}{4 d}+2 a b x+\frac{b^2 \tanh (c+d x)}{d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.036, size = 51, normalized size = 1.1 \begin{align*}{\frac{1}{d} \left ({a}^{2} \left ({\frac{\cosh \left ( dx+c \right ) \sinh \left ( dx+c \right ) }{2}}+{\frac{dx}{2}}+{\frac{c}{2}} \right ) +2\, \left ( dx+c \right ) ab+{b}^{2}\tanh \left ( dx+c \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.13703, size = 85, normalized size = 1.81 \begin{align*} \frac{1}{8} \, a^{2}{\left (4 \, x + \frac{e^{\left (2 \, d x + 2 \, c\right )}}{d} - \frac{e^{\left (-2 \, d x - 2 \, c\right )}}{d}\right )} + 2 \, a b x + \frac{2 \, b^{2}}{d{\left (e^{\left (-2 \, d x - 2 \, c\right )} + 1\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.14895, size = 196, normalized size = 4.17 \begin{align*} \frac{a^{2} \sinh \left (d x + c\right )^{3} + 4 \,{\left ({\left (a^{2} + 4 \, a b\right )} d x - 2 \, b^{2}\right )} \cosh \left (d x + c\right ) +{\left (3 \, a^{2} \cosh \left (d x + c\right )^{2} + a^{2} + 8 \, b^{2}\right )} \sinh \left (d x + c\right )}{8 \, d \cosh \left (d x + c\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.16317, size = 180, normalized size = 3.83 \begin{align*} \frac{a^{2} e^{\left (2 \, d x + 2 \, c\right )}}{8 \, d} + \frac{{\left (a^{2} + 4 \, a b\right )}{\left (d x + c\right )}}{2 \, d} - \frac{a^{2} e^{\left (4 \, d x + 4 \, c\right )} + 4 \, a b e^{\left (4 \, d x + 4 \, c\right )} + 2 \, a^{2} e^{\left (2 \, d x + 2 \, c\right )} + 4 \, a b e^{\left (2 \, d x + 2 \, c\right )} + 16 \, b^{2} e^{\left (2 \, d x + 2 \, c\right )} + a^{2}}{8 \, d{\left (e^{\left (4 \, d x + 4 \, c\right )} + e^{\left (2 \, d x + 2 \, c\right )}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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